Question

find the median for this pls​

Answer 1

Answer:

30

Step-by-step explanation:

6+9+14+2+19+10=60

Answer 2

S O L U T I O N :

$\underline{\bf{Given\::}}$

Class - Interval = 0 - 10, 10 - 20, 20 - 30, 30 - 40, 40 - 50, 50 - 60

Frequency =          6           9           14            2           19           10

$\underline{\bf{Explanation\::}}$

Data represent :

$\begin{tabular}{|c|c|c|} \cline{1-3} \multicolumn{3}{|c|}{DATA}\\ \cline{1-3} \bf Class - Interval & \bf Frequency, (f) & \bf Cumulative - frequency } \\ \cline{1-3} 0-10 & 6 & 6 \\ 10-20 & 9 & 15 \\ 20-30 & 14 & 29 \\ 30-40 & 2 & \bf M = 31 \\ 40-50 & 19 & 50\\ 50-60 & 10& 60 \\ \cline{1-3} & \sf N = \sf \Sigma \sf f = \sf 60 & \\ \cline{1-3 } \end{tabular}$

A/q

As we know that formula of the median;

$\boxed{\bf{Median = l +\bigg( \frac{n/2 - CF}{f}\bigg) \times h}}$

We have :

• l = 30
• CF = 30
• f = 2
• h = 10
• N = 60

$\longrightarrow\tt{Median = l +\bigg(\dfrac{n/2 - CF}{f} \bigg) \times h}$

$\longrightarrow\tt{Median = 30 +\bigg(\dfrac{60/2 - 30}{2} \bigg) \times 10}$

$\longrightarrow\tt{Median = 30 +\bigg(\dfrac{\cancel{60/2} - 30}{2} \bigg) \times 10}$

$\longrightarrow\tt{Median = 30 +\bigg(\dfrac{30- 30}{2} \bigg) \times 10}$

$\longrightarrow\tt{Median = 30 +\dfrac{0}{2} \times 10}$

$\longrightarrow\tt{Median = 30 + 0 \times 10}$

$\longrightarrow\tt{Median = 30 + 0 }$

$\longrightarrow\bf{Median = 30}$

Thus,

The median of these data will be 30 .