Question

Find the Median from the following table ci below 140 145-150 150-155 155-160 160-165 F 4 7 18 11 6 5

Answer 1

Answer:

Where cf= cumulative frequency

Median =1+

⎩

⎪

⎪

⎪

⎨

⎪

⎪

⎪

⎧

h×

f

(

2

N

−cf)

⎭

⎪

⎪

⎪

⎬

⎪

⎪

⎪

⎫

Here

N=100

N/2=50

cf just greater than 50 is 56

Median class =150−155

So, I=150, h=5, f=22 and

cf=cf of preceding class i.e 34

Substitute all the value in the above formula, we get

Median =150+{5×(50−34)/22}

=150+3.64

=153.64

Step-by-step explanation:

I hope this will help you