Question

find the median from the following table: Marks: 0_10, 10_20, 20_30, 30_40, 40_50. no. of students: 8, 30, 40, 12, 10? Describe this question and solutions. iska answer 23 aa rha h​

Answer 1

Easy one

the question says that we need to find the median and median Is the middle most value of any data.

here , CI(class intervals) = mArks , f(frequency)= no. of studentS)

and cf(cumulative frequency)

CI          f       cf

0-10       8        8

10-20     30      38 (30+80

20-30    40      78 (38 +40)

30-40    12       90  (78 + 12)

40-50    10      100 (90 +10)

         n =100

n/2  = 50 (for findinG tHe median class)

as , we need to look up for a CF which has a number = or just greater than n/2

therefore,

median class = 20---30

l = 20 , h = 10 , cfo = 38  ,  f  = 40

now, we know that

$median = l+ (\frac{\frac{n}{2}-cfo}{f}) * h$

on substituting the values, we get

$= 20+ (\frac{50 - 38}{40} }) * 10$

$= 20+ (\frac{12}{4}})$

$= 20+ 3$

= 23

median = 23

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Answer 2

Answer:

$\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}$

Step-by-step explanation:

In this question , we need to find the median of the data.

{hint for median } — median always lies in between median class .

now to calculate median , we need to first see the highest frequency:

( see there in image ]

here,

median class = 20-30.

lower limit of median class ,l = 20

class size = 30-20 = 10

frequency of median class = 40

CF = 38

also, n = 100

as we know that,

median = l + [n/2-CF/f]×h

=> 20 + [ 50 -38/40]×10

=> 20 + 12/4

= 20 + 3

= 23

Also, for verification you can check that median has come between the median class .I hope this will help you.

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$\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}$