Question

find the median of 8, 15, 23, 14, 6, 8, 3, 16, 15 and 18​

Answer 1

Data : 8,15,23,14,6,8,3,16,15,18

Arranging the data in ascending order :

3,6,8,814,15,15,16,18,23

Then ,

They are even in numbers so ,

Median =

$\frac{ \frac{n}{2}th + (\frac{n}{2} + 1 )th}{2} \\ \\ \frac{ \frac{10}{2}th + (\frac{10}{2} + 1) th}{2} \\ \\ \frac{5 \: th+ 6 \: th}{2}$

5 th term = 14

6 th term = 15

$\frac{14 + 15}{2} = \frac{29}{2} = 14.5$

The required median = 14.5

Answer 2

Hey there!

Answer:

Median  = 14.5

Step-by-step explanation:

♣ Given Data:

8, 15, 23, 14, 6, 8, 3, 16, 15 and 18​

♣ Arranging in ascending order:

3, 6, 8, 8, 14, 15, 15, 16, 18, 23

Here n = 10  (even).

♣ Apply Median formula:

$\sf Medain = \dfrac{1}{2}\Bigg[\Bigg(\dfrac{n}{2}\Bigg)th \ term + \Bigg(\dfrac{n}{2}+1\Bigg)th term\Bigg]$

$\sf Medain = \dfrac{1}{2}\Bigg[\Bigg(\dfrac{10}{2}\Bigg)th \ term + \Bigg(\dfrac{10}{2}+1\Bigg)th term\Bigg]$

$\sf Medain = \dfrac{1}{2}\Bigg[5th \ term + 6 th\ term\Bigg]$

$\sf Medain = \dfrac{1}{2}\bigg[14+15\bigg]\\\\\sf Medain = \dfrac{1}{2} \times 29\\\\Medain = 14.5$

Hope it Helps You!