Question

find the median of data 10 17 32 21 19 22 9 35​

Answer 1

Answer:

Step-by-step explanation:

First aarange in increasing order then take out middle term

Ans is

In this case middle terms r two so add them and divide by 2

20 is median

Answer 2

$\Large\frak{\underline{\underline{Correct \: Question:}}}$

35,32,35,42,38,32,34

Find the Mean,Median and Mode of data.

$\rule{170}2$

$\Large\frak{\underline{\underline{Your~Answer:}}}$

$\underline{\bigstar\:\textsf{Mean \: of \: data:}}$

$\maltese\:\:\:\boxed{\normalsize\sf\ Mean = \frac{Sum \: of \: all \: observations}{Number \: of \: total \: observations}}\\\\\\\normalsize\ : \implies\sf\ Mean = \scriptsize\frac{(35,32,35,42,38,32,34)}{7}\\\\\\\normalsize\ : \implies\sf\ Mean = \frac{\cancel{248}}{\cancel{7}}\\\\\\\normalsize\ : \implies\sf\ Mean = 35.42\\\\\\\normalsize\ : \implies{\underline{\boxed{\sf \red{ Mean = 35.42}}}}$

$\underline{\bigstar\:\textsf{Median \: of \: data:}}\\ \\ \normalsize\sf\bullet\: Arrange \: the \: data \: into \: ascending \: order:\\ 32,32,34,35,35,38,42\\ns(n) = 35 = odd \: number \\\\\maltese\:\:\boxed{\sf\ Median = \frac{n +1}{2}^{th} \: term}\\\\\\\normalsize\ : \implies\sf\ Median = \frac{35 + 1}{2}^{th} \: term\\\\\\\normalsize\ : \implies\sf\ Median = \frac{\cancel{36}}{\cancel{2}}^{th} \: term\\\\\\\normalsize\ : \implies\sf\ Median = 8^{th} \: term\\\\\\\normalsize\ : \implies\sf\ Median = 72\\\\\\\normalsize\ : \implies{\underline{\boxed{\sf \red{Median = 72 }}}}$

$\underline{\bigstar\:\textsf{Mode \: of \: data:}}\\\\ \sf\ Reference \: of \: occuring \: of \: outcomes \: is \\ \sf\ shown \: in \: table:$

$\boxed{\begin{tabular}{ c || c} \bf{Observation} & \bf{Times of occurring}\\ \cline{1-2}\sf{32} & \sf{2} \\ \cline{1-2}\sf{34} & \sf{1}\\ \cline{1-2}\sf{35} & \sf{2}\\ \cline{1-2}\sf{38} & \sf{1}\\ \cline{1-2}\sf{42} & \sf{1}\\ \end{tabular}}$

$\normalsize\sf\ From \: the \: observations \: it \: is \: quite \: simple \: \\ \sf\ to \: know \: that \: 32(2)and\:35(2)\: has \: highest \: times \: of \: occurring \\\\\\\maltese\:\:\boxed{\sf\ Mode = Maximum \: number \: of \: occuring}\\\\\\ \normalsize\ : \implies\sf\ Mode = 32\:and\:52 \\\\\\\normalsize\ : \implies{\underline{\boxed{\sf \red{ Mode = 32\:and\:35}}}}$