Math, asked by surajitsadhukhan4000, 5 hours ago

Find the median of marks : 4, 12, 7, 9, 14, 17, 16, 21. *

Answers

Answered by musaibnazir182
0

Answer:

Let us arrange the data in ascending order.

Mode - 12,12,13,13,14,14,14,16,19

Here, 14 occurs the maximum numbers of times, hence its the mode.

Median, \left(\frac{n+1}{2}\right)th\ term\(

2

n+1

)th term

n = 9

= \frac{9+1}{2}\ =\ 5th\ term

2

9+1

= 5th term

= 14

Mode = 14

Median = 14

Answered by gayatrikumari99sl
0

Answer:

13 is the required median of the given mark.

Step-by-step explanation:

Explanation:

Given in the question, 4 , 12,7, 9, 14 ,17, 16, 21.

  • Median - Divide the total number of numbers in the data collection by the sum of all the numbers.
  • The centre of a data set is represented by the median. Place the data points in descending order of size to find the central number.
  • To find the median of a set of numbers, the first step is to arrange the numbers either in ascending order or descending order.

Step 1:

Arrange the set of numbers in ascending order,

⇒ 4 , 7 , 9 , 12, 14, 16 ,17 , 21

Total number of term (n) = 8

Median = \frac{(\frac{n}{2}th) +(\frac{n}{2}+1  )th }{2}

⇒ Median = \frac{(\frac{8}{2}) th + (\frac{8}{2} +1)th}{2}

⇒Median = \frac{4th + 5th}{2}

So, 4th term is 12 and 5th term is 14.

⇒ Median = \frac{12 + 14}{2} = \frac{26}{2} = 13

Final answer:

Hence, the median is 13.

#SPJ3

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