find the median of sin²90,tan²45,sec²45 ,cosec45,tan²60,cos²90,sec²60
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Answer:
cos² 30° + sin² 60° + tan² 45° + sec² 60° + cos 0°
= √3
² + √3
² + (1)² + (2)² + 1
2 2
=
3
+
3
+ 1 + 4 + 1
4 4
= 6 +
3 + 3
4
= 6 +
6
= 6 +
3
=
12 + 3
4 2 2
=
15
= 7
1
2 2
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