Question

. Find the median of the following

20, 29, 28, 33, 25, 43, 38, 42​

Answer 1

${ \huge{\boxed{\underline{\colorbox{pink}{\textsf{ \textbf{ \color{red}{Required Answer:}}}}}}}}$

To Solve:

20, 29, 28, 33, 25, 43, 38, 42 - It's Median

Solⁿ:

Sort them in ascending order:

20, 25, 28, 29, 33, 38, 42, 43

No. of terms (n) - 8 (even)

${ \sf{ \frac{n}{2} th \: \: and \: \: ( \frac{n}{2} th \: + \: 1)}}$

${ \sf{ \frac{8}{2} =4 \: th \: term}}$

${ \sf{ \frac{8}{2} th + 1 = 5 \: th \: \: term \: }}$

${ \sf \frac{29 + 33}{2} = \frac{62}{2}} \\ \\ { \boxed{ \sf{ \blue{ median \: = 31}}}}$

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Answer 2

$\star\underline{\mathrm\color{aqua}{⫷❥A} \mathbb\color{red}{N~ }\mathtt\color{blue}{S} \mathbb\color{purple}{W} \mathtt\color{orange}{E} \mathbb\color{red}{R⫸}}\star\:$

The median of the given data = 33

Step-by-step explanation:

The given data:

✯20, 29, 28, 33, 42, 38, 43, 25, 40✯

✯To find, the median of the given data = ?✯

➪The given data in ascending order :

• 20, 25, 28, 29, 33, 38, 40, 42 and 43

• Here, the total number of data = 9, which is odd

• We know that,

$\rm Median = \dfrac{n+1}{2}th$

$\sf = \dfrac{9+1}{2}th \:term$

= 5th term

= 33

⟹ ∴ The median of the given data = 33

✵Thus, the median of the given data is 33.✵