Question

Find the median of the following data .
12,20,33,40,42,50,62,70.​

Answer 1

Answer:

median : 40+42/2

82/2

41

Answer 2

★GIVEN★

Following data .

12,20,33,40,42,50,62,70.

★To Find★

The median.

★SOLUTION★

In ascending order:-

12,20,33,40,42,50,62,70

Total number of terms (n) = 8

As the no of terms is 8 it is even.

The formula,

$\large{\orange{\underline{\boxed{\bf{\left[\dfrac{\left\Bigg(\dfrac{n}{2}\right\Bigg)th\:term+\left\Bigg(\dfrac{n}{2}+1\right\Bigg)th\:term}{2}\right]}}}}}$

According to the question,

$\large\implies{\sf{\left\Bigg[\dfrac{\left\Bigg(\dfrac{n}{2}\right\Bigg)th\:term+\left\Bigg(\dfrac{n}{2}+1\right\Bigg)th\:term}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{\left\Bigg(\dfrac{8}{2}\right\Bigg)th\:term+\left\Bigg(\dfrac{8}{2}+1\right\Bigg)th\:term}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{4\:th\:term+(4+1)th\:term}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{4\:th\:term+5\:th\:term}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{40+42}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{82}{2}\right\Bigg]}}}}}$

$\large\implies{\sf{\left\Bigg[\dfrac{\cancel{82}}{\cancel{2}}\right\Bigg]}}}}}$

$\large\therefore\boxed{\bf{Median=21.}}}}}$

$\large{\orange{\underline{\boxed{\therefore{\bf{Median=21.}}}}}}$

N. B. -- Check the answer from web