Find the median of the following data ,41,43,127,99,61,92,71,58,57. If 58is replaced by 85 what will be the new median?
Answers
Answered by
227
Hi friend !
Let's arrange them in ascending order[increasing order]:-
41,43,57,58,61,71,92,99,127
No: of observations = n = 9 [ odd]
Median = n + 1/2
= 10/2 = 5th observation
= 61
------------------------------------
if 58 is replaced by 85 :, the order of no:s would be :-
41,43,57,61,71,85,92,99,127
no: of observations = n = 9
median = n + 1/2
= 10/2
= 5th observation
=71
71 is the new median !
Let's arrange them in ascending order[increasing order]:-
41,43,57,58,61,71,92,99,127
No: of observations = n = 9 [ odd]
Median = n + 1/2
= 10/2 = 5th observation
= 61
------------------------------------
if 58 is replaced by 85 :, the order of no:s would be :-
41,43,57,61,71,85,92,99,127
no: of observations = n = 9
median = n + 1/2
= 10/2
= 5th observation
=71
71 is the new median !
Chrisanil456:
Thank u so much
Answered by
0
Answer:
correct option is A 71
given that
41,43,127,99,61,92,71,58,57
arrange the data in ascending order
41,43,57,58,61,71,92,99,127
Here observe that No' of observations (n) are odd i.e n=9
So median is 2n+1 th term
Median =2n+1th term =n9+1 th term
=5 th term
=61
58 is replaced by 85
then new data is
41,43,57,85,61,71,92,99,127
arrange the data in ascending order
41,43,57,61,71,85,92,99,127
Here observe that no's observation are odd i.e n=9
So
median is 2n+1th term
Median =29+1 th term
=5th term
=71
∴ new median =71
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