Question

Find the median of the following data.

Height (in cm) -------------- No of Students
less than 120 --------------- 12
less than 140 --------------- 26
less than 160 --------------- 34
less than 180 --------------- 40
less than 200 --------------- 50

Answer 1

Answer:

Half of the values are above 141.67, and half are below.

Step-by-step explanation:

We have

N=50

N/2=50/2 =50

The cumulative frequency just greater than N/2 is 26. Therefore, the median class is 120-140.

To get the median, we will use the equation:

$Median = L+(\frac{\frac{N}{2} -F}{f}) h$

L = lower boundary of the median class

N = sum of frequencies

F = cumulative frequency before the median class.

f = frequency of the median class

h = the size of the median class

  =140-120 = 20

$Median = L+(\frac{\frac{N}{2} -F}{f}) h$

= 120+[(50/12-12)/12] x20

=120+[(25-12)/12]x20

=120+(13/12)x20

=120+21.67

=141.67

Answer 2

Answer:

the median is 141.67

Step-by-step explanation:

hope this hand-written sol helps you