History, asked by khuhsi079, 1 month ago

Find the median of the following data Marks 20-30 30-40 40-50 50-60 60-70 70-80 80-90 frequency 5 15 25 20 7 8 10

Answers

Answered by hotcupid16
41

\sf \bold{\underline{Question:-}}\\ \\

Find the median of the following data :

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\begin{tabular}{|c|c|c|c|c|c|c|c|}\cline{1-8} Class&20 - 30& 30 - 40  & 40 - 50&50 - 60&60 - 70&70 - 80&80 - 90\\\cline{1-8}Frequency&5&15&25&20&7&8&10\\\cline{1-8}\end{tabular}

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\sf \bold{\underline{AnswEr:-}}\\ \\

\boxed{\begin{array}{cccc}\bf Class\: interval&\bf Frequency\: (f) &\bf C.F\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf 20 - 30&\sf 5&\sf 5\\\\\sf 30 - 40 &\sf 15&\sf 20\\\\\sf 40 - 50&\sf 25&\sf 45\\\\\sf 50 - 60&\sf 20&\sf 65\\\\\sf 60 - 70&\sf 7&\sf 72\\\\\sf 70 - 80&\sf 8&\sf 80\\\\\sf 80 - 90&\sf 10&\sf 90\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf & \bf \sum f = 90& \end{array}}

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We know that,

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\boxed{\begin{minipage}{6cm}$\bigstar$\:\:\sf Median = l + $\sf\dfrac{\frac{n}{2}-C.f.}{f}\times h\\\\Here: \\ \\1)\:N =  \sum \:f= 90\\2)\:l=Lower\:limit\:of\:median\:class=40\\3)\:C.f.=Cumulative\:frequency\:of\:class\\preceeding\:the\:median\:class=20\\4)\:f= frequency\:of\:median\:class=25\\5)\:h= Class\:interval =40-30=10\end{minipage}}

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\underline{\bigstar\:\boldsymbol{According\; to \;the \;Question :}} \\  \\

\dashrightarrow\sf\:\:\purple{Median = l +\dfrac{\frac{n}{2}-C.f.}{f}\times h}\\\\\\\dashrightarrow\sf\:\:Median = 40 +\bigg\lgroup\dfrac{45-20}{25}\times10\bigg\rgroup\\\\\\\dashrightarrow\sf\:\:Median = 40 +\bigg\lgroup \cancel{\dfrac{25}{25}}\times10\bigg\rgroup\\\\\\\dashrightarrow\sf\:\:Median = 40 +10\\\\\\\dashrightarrow\:\:\underline{\boxed{\pink{\sf Median = 50}}}\;\bigstar

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\therefore\:\underline{\textsf{Median of given data is \textbf{50}}}.

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