find the median of the following data
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Answer:
50or above
43 is the median
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Answer:
ClassInterval Frequency c.f.
ClassInterval Frequency c.f. 0−20 6 6
20−40 8 14
40−60 10 24
60−80 12 36
80−100 6 42
100−120 5 47
120−140 3 50
120−140 3 50
N=50
Here, N=50, then
2
2N
2N
=
= 2
= 250
= 250
= 250
=25
∴ Median class =60−80
We have, l=60,c.f=24,f=12 and h=20
We have, l=60,c.f=24,f=12 and h=20Median=l+
f
f2
f2N
f2N
f2N −c.f
f2N −c.f
f2N −c.f ×h
f2N −c.f ×h =60+
12
1225−24
1225−24
1225−24 ×20
1225−24 ×20 =60+1.66
1225−24 ×20 =60+1.66 =61.66
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