Math, asked by vegadantrix, 6 months ago

Find the median of the following frequency distribution:

Wages(in Rs) 200-300 300-400 400-500 500-600 600-700

No. Of Laborers 3 5 20 10 6​

Answers

Answered by saraswatikrisaraswat
1

Answer:

cjjdkdidlfd8sisitsdjsitsjsisdkd

Step-by-step explanation:

o6t6oluflufkgb

xmhxcmldkldu

Answered by kwin15
5

Step-by-step explanation:

Here n=400. ∴

2

n

=200

Class Frequency Cumulative frequency(c.f.)

0-100 64 64

100-200 62 64+62=126

200-300 84 126+84=210

300-400 72 210+72=282

400-500 66 282+66=348

500-600 52 348+52=400

Cumulative frequency greater than 200 is 210, corresponds to the class 200−300.

Class 200−300 is the median class

l=200,

2

n

=200,cf=126,f=84 and c=100

Substituting the values in

M=l+

f

(

2

n

−cf)

×c

=200+

84

200−126

×100

=200+

84

74×100

=200+88.10

=288.10

Similar questions