Find the median of the following
observations.
Class interval:0-20 20-40 40-60 60-80
80-100 100-120.
Frequency:10 35 52 61 38 29
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1
median = l+ (n/2 - CF)/ f ×h ...
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Answered by
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Answer:
Lifetime
(in hours) No. of components
0-20 10
20-40 35
40-60 52
60-80 61
80-100 38
100-120 29
As frequency is maximum for the class 60−80, modal class is 60−80.
Mode=l+
2f
1
−(f
0
+f
2
)
f
1
−f
0
×h
where,
l = lower limit of modal class =60
f
1
= frequency of modal class =61
f
0
= frequency of class preceding the modal class =52
f
2
= frequency of class succeding the modal class =38
h= higher limit - lower limit =80−60=20
Mode=60+
2×61−(52+38)
61−52
×20
⇒mode=60+
32
9
×20=60+5.625=65.625
Hence, the modal lifetimes of the components are 65.625 hrs.
Explanation:
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