find the median of the following table class:-3,6,9,12,15,18
frequency:- 6,12,9,14,24,11
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Answer:
Answer
x
10
11
12
13
14
15
f
1
4
7
5
9
8
for a frequency distribution,
So, total number of observation =(1+4+7+5+9+8)=34
It is a even number.
So, median is the value of average of values at (
2
n
)
th
and (
2
n+2
)
th
.
∴ Here, median is the average of the values at (
2
34
)
th
or 17
th
position and (
2
34+2
)
th
or 18
th
position.
x 10 11
12
13
14
15
f
1
4
7
5 9
8
position
1
1+4=5
5+7=12
12+5=17
17+9=26
26+8=34
So, value of x at 17
th
position is 13 and at 18
th
position is 14.
∴Median=(
2
13+14
)=
2
27
=13.5.
Mode for a frequency distribution is the value which is the most common frequent value.
Here 14 has frequency 9 which is highest. So, mode for the frequency distribution is 14.
,, ..
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