find the men proportionl to 0.32and 0.08
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Let the mean proportional between 0.32 and 0.08
Then, 0.32:x:x:0.08
product of extreme =product of means
x×x=0.32×0.08
x2 =0.0256
x=0.16
Hence , the mean proportional between 0.32 and 0.08 is 0.16
Then, 0.32:x:x:0.08
product of extreme =product of means
x×x=0.32×0.08
x2 =0.0256
x=0.16
Hence , the mean proportional between 0.32 and 0.08 is 0.16
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