Question

Find the mesaure of the angle of a triangle if its angle is 80 and the other two angle are in the ratio3ratio7​

Answer 1

${\large{\bf{\red{\clubs{\underline{Given :}}}}}}$

The angles of a triangle are 80° and other two angles are in the ratio 3 : 7.

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${\large{\bf{\blue{\clubs{\underline{To Find:}}}}}}$

Find the measure of the rest two angles.

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${\large{\bf{\orange{\clubs{\underline{Solution :}}}}}}$

Remember that :

${\sf{\purple{Sum \: of \: all \: sides \: of \: triangle = 180°}}}$

Now, let ratios be x :

${\sf{\purple{1st \: angle = 80°}}}$

${\sf{\purple{2nd \: angle = 3x}}}$

${\sf{\purple{3rd \: angle = 7x}}}$

Than,

${\sf{\green{80° + 3x + 7x = 180°}}}$

${\sf{\green{80° + 10x = 180°}}}$

${\sf{\green{10x = 180° - 80°}}}$

${\sf{\green{x ={\cancel \frac{100}{10} }}}}$

${\sf{\red{X = 10}}}$

So,

${\bf{\red{\mapsto{1st \: angle = 80°}}}}$

${\bf{\red{\mapsto{2nd \: angle = 3x = 3 \times 10 = 30°}}}}$

${\bf{\red{\mapsto{3rd \: angle = 7x = 7 \times 10 = 70°}}}}$

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${\sf{\pink{\blue{\fcolorbox{green}{red}{\underline{XitzNobitaxX}}}}}}$

Answer 2

Answer:

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${\bf{\red{\mapsto{1st \: angle = 80°}}}}$

${\bf{\red{\mapsto{2nd \: angle = 3x = 3 \times 10 = 30°}}}}$

${\bf{\red{\mapsto{3rd \: angle = 7x = 7 \times 10 = 70°}}}}$

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