Question

Find the mid-point of a line segment AB, if the coordinates of A (2,5) and B (-4,-3).

please help me​

Answer 1

Answer:

Let the coordinates of A and Bare (x, 0) and (0, y).

So x = mx2+ nx1/ m + n, y = my2 + ny1/m + n

m = 2, n = 3

x1 = 4, x2 = 4

y1 = - 5, y2 = 5

∴ x = 2 × 3 + 3 × 4/2 + 3 = 8 + 12/5 = 20/5 = 4

y = 2 × 5 + 3 × – 5/2 + 3

= 10 – 15/5 = - 5/5 = - 1

∴ Co-ordinate of P are (4, - 1)

Thus, the coordinate of midpoints of

AB = (x + 0/2, y + 0/2)

= (x/2, y/2)

According to question, the coordinate of mid-point = (4, - 3)

∴ x/2 = 4, x = 8

y/2 = - 3, y = - 6

∴ The required points are (8, 0) and (0, - 6).

I hope that this answer helpful to you........

Answer 2

Answer:

$\huge{ \underline{ \underline{ \red{ \pink{ \green{ \purple{ \orange{a}{n} }{s} }{w} }{e} }{r} }{} }{} }{}$

Refer the attachment

So required pionts are (8, 0), (0, 6)