Question

Find the mid point of AB if the co ordinates of A and B are (a, - a) and (- a, a) respectively.​

Answer 1

$\huge{\underline{\sf Solution:-}}$

• A(a,-a)
• B(-a,a)

We know that

$\boxed{\sf Mid\:point=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)}$

$\\ \tt{:}\dashrightarrow \left(\dfrac{a+(-a)}{2},\dfrac{-a+a}{2}\right)$

$\\ \tt{:}\dashrightarrow\left(\dfrac{a+a}{2},\dfrac{0}{2}\right)$

$\\ \tt{:}\dashrightarrow \left(\dfrac{2a}{2},0\right)$

$\\ \tt{:}\dashrightarrow Mid:point=(a,0)$

Answer 2

Answer:

a,0 is the answer

hope it helps you