Question

Find the mid point of line joining (2,3),(4,5)​

Answer 1

Answer- The above question is from the chapter 'Coordinate Geometry'.

Concept used: Mid point formula:-

Let P (x, y) be the midpoint of a line joining A (x₁, y₁) and B (x₂, y₂).

Then, $x = \dfrac{x_{1} + y_{1}}{2} \: and \: y= \dfrac{y_{1} + y_{2}}{2}$ .

Given question: Find the mid point of line joining (2, 3) and (4, 5)​.

Solution: Let P (x, y) be the mid point of line joining A (2, 3) and B (4, 5).

$x = \dfrac{x_{1} + x_{2}}{2}\\x = \dfrac{2 \: + \: 4}{2}\\x = \dfrac{6}{2}$

x = 3

$y = \dfrac{y_{1} \: + y_{2}}{2}\\\\y = \dfrac{3 \: + \: 5}{2}\\\\y = \dfrac{8}{2}$

y = 4

P (x, y) ⇒ P (3, 4)

∴ P (3, 4) is the mid point of line joining (2, 3) and (4, 5)​.

Answer 2

Answer:

Answer- The above question is from the chapter 'Coordinate Geometry'.

Concept used: Mid point formula:-

Let P (x, y) be the midpoint of a line joining A (x₁, y₁) and B (x₂, y₂).

Then, x = \dfrac{x_{1} + y_{1}}{2} \: and \: y= \dfrac{y_{1} + y_{2}}{2}x=

2

x

1

+y

1

andy=

2

y

1

+y

2

.

Given question: Find the mid point of line joining (2, 3) and (4, 5).

Solution: Let P (x, y) be the mid point of line joining A (2, 3) and B (4, 5).

\begin{gathered}x = \dfrac{x_{1} + x_{2}}{2}\\x = \dfrac{2 \: + \: 4}{2}\\x = \dfrac{6}{2}\end{gathered}

x=

2

x

1

+x

2

x=

2

2+4

x=

2

6

x = 3

\begin{gathered}y = \dfrac{y_{1} \: + y_{2}}{2}\\\\y = \dfrac{3 \: + \: 5}{2}\\\\y = \dfrac{8}{2}\end{gathered}

y=

2

y

1

+y

2

y=

2

3+5

y=

2

8

y = 4

P (x, y) ⇒ P (3, 4)

∴ P (3, 4) is the mid point of line joining (2, 3) and (4, 5)