Find the mid point of line segment Joining the point (1,6) & (4,3)
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Answer:
(3m,6) and B(−4,3n) be C(1,2m−1).
Here x
1
=3m,y
1
=6,x
2
=−4,y
2
=3n
x=1,y=2m−1
∴ By Midpoint formula, x=(x
1
+x
2
)/2
∴1=(3m+−4)/2
∴3m−4=2
∴3m=2+4
∴3m=6
∴m=6/3=2
∴ By Midpoint formula, y=(y
1
+y
2
)/2
∴2m−1=(6+3n)/2
∴4m−2=6+3n
Put m=2 in above equation,
∴4×2−2=6+3n
∴8−2−6=3n
∴3n=0
∴n=0
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