find the mid point of side bc. if the centroid of triangle abc is (5,3) and vertex a is (-4,1)
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ABC is a triangle whose centroid G(2,3) ,
A(5,6) .
let coordinates of B(h,k) and C(p,q).
x coordinate of G=(5+h+p)/3.
2 = (5+h+p)/3.
5+h+p = 6 . or h+p = 1…………..(1).
y coordinate of G=(6+k+q)/3.
3 = (6+k+q)/3.
6+k+q = 9 . or k+q = 3…………….(2)
Mid point of BC = [(h+p)/2, (k+q)/2].
put h+p = 1 from eq.(1) and k+q = 3 from eq.(2).
mid point of BC = (1/2,3/2) . Answer
A(5,6) .
let coordinates of B(h,k) and C(p,q).
x coordinate of G=(5+h+p)/3.
2 = (5+h+p)/3.
5+h+p = 6 . or h+p = 1…………..(1).
y coordinate of G=(6+k+q)/3.
3 = (6+k+q)/3.
6+k+q = 9 . or k+q = 3…………….(2)
Mid point of BC = [(h+p)/2, (k+q)/2].
put h+p = 1 from eq.(1) and k+q = 3 from eq.(2).
mid point of BC = (1/2,3/2) . Answer
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Answer:
Step-by-step explanation:ABC is a triangle whose centroid G(2,3) ,
A(5,6) .
let coordinates of B(h,k) and C(p,q).
x coordinate of G=(5+h+p)/3.
2 = (5+h+p)/3.
5+h+p = 6 . or h+p = 1…………..(1).
y coordinate of G=(6+k+q)/3.
3 = (6+k+q)/3.
6+k+q = 9 . or k+q = 3…………….(2)
Mid point of BC = [(h+p)/2, (k+q)/2].
put h+p = 1 from eq.(1) and k+q = 3 from eq.(2).
mid point of BC = (1/2,3/2) .
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