Question

find the mid point of( sin^2 alpha,sec^2alpha ) and( cos ^2 aplha -tan^2alpha)​

Answer 1

Step-by-step explanation:

Mid point of line whose end points are (x1,y1) and (x2,y2) respectively is given by (xm, ym)

Where xm= (x1 + x2)/2 and ym= (y1+y2)/2

So mid point's x coordinate will be

xm = (sin^2a + cos^2a)/2 = 1/2 ( as sin^2theta + cos^2theta = 1 )

ym = (sec^2a-tan^2a)/2 = 1/2

So coordinates of mid point are (1/2,1/2)