Question

find the mid point of the line segment connections the two points (5,-3) (-4,7)

Answer 1

Required Answer:-

The midpoint of the line joining the points (a1, b1) and (a2, b2) is given by:

␥${ \boxed{ \rm{ \frac{a1 + a2}{2} ,\frac{b1 + b2}{2} }}}$

Here the points are (5,-3) and (-4,7). According to formula,

• a1 = 5
• a2 = -4
• b1 = -3
• b2 = 7

Then,

➙ Midpoint = (5 + -4/2, -3 + 7/2)

➙ Midpoint = (1/2, 4/2)

➙ Midpoint = (1/2,2) (B)

Note:-

• In coordinate geometry, always try to draw simple diagrams (rough sketch) to imagine the situation and finalize your answer.
• Learn and derive all the formulas in your curriculum.

Answer 2

$\huge \blue{\boxed{\bf \orange {\bigg(\frac{1}{2} , 2 \bigg)}}}$

Step-by-step explanation:

QUESTION :-

Find the midpoint of the line segment connecting the two points.

(5, -3) , (-4, 7)

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SOLUTION :-

Let the two points as

$\bf A ({x}_{1} , {y}_{1}) = (5 , - 3)$

$\bf => {x}_{1} = 5 , {y}_{1} = - 3$

$\bf \& B ({x}_{2} , {y}_{2}) = (- 4 , 7)$

$\bf => {x}_{2} = - 4 , {y}_{2} = 7$

$\:$

Using the midpoint formula :-

$\large \red {\boxed{\bf \blue {Midpoint = \bigg(\dfrac{{x}_{1} + {x}_{2}}{2} , \dfrac{{y}_{1} + {y}_{2}}{2} \bigg)}}} \\ \\ => \bf Midpoint = \bigg(\frac{5 + (-4)}{2} , \frac{-3+7}{2} \bigg) \\ \\ => \bf Midpoint = \bigg(\frac{5-4}{2} , \frac{4}{2} \bigg) \\ \\ => \bf \red{ Midpoint = \bigg(\frac{1}{2} , 2 \bigg)}$

Hence,

The Midpoint of AB is (1/2, 2) [option B]

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Hope it helps.

#BeBrainly :-)