Question

Find the mid points of the sides of a triangle whose vertices are (0,1) (2,1) (0,3). Hence find the length of the medians​

Answer 1

Answer:

Step-by-step explanation:

let A 〈 0, - 1 〉 B 〈 2 , 1 〉 C 〈 0 , 3 〉 vertices of ΔABC

Mid point of AB, L Ξ [ ( 0 + 2 ) / 2 , (-1 + 1) /2 ]

L Ξ ( 1 , 0 )

mid point BC , M Ξ [ ( 2+ 0 ) / 2 , ( 1+ 3 ) /2 ]

M Ξ ( 1 , 2 )

Mid point of CA , N Ξ [ (0+0) /2 , (-1 + 3 ) /2 ]

N Ξ ( 0 , 1 )

Now Medians are CL, BN, AM

A ( 0, -1) M(1, 2)

AM = √ ( 1-0)² + (-1 -2) ² = √ 10

CL = √ 10

BN = √ 4 = 2

Answer 2

Step-by-step explanation:

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