Find the middle most term of the A.P -11,-7,-3...........,49
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Answered by
477
-11,-7 , -3 ......,49 is in AP
first term = a = -11
common difference =d = a2- a1= -7-(-11) = -7 +11 = 4
last term = l = 49
a +(n-1)d =49
-11+(n-1)4 =49
(n-1)4 =49+11
(n-1)4 = 60
n-1 = 60/4
n-1 = 15
n= 15 +1 =16
number of terms are in AP is 16
middle terms or 8th and 9th terms
a8 = a+7d = -11+7*4 = -11+28 = 17
a9 = a +8d = -11+8*4 =-11+32 = 21
first term = a = -11
common difference =d = a2- a1= -7-(-11) = -7 +11 = 4
last term = l = 49
a +(n-1)d =49
-11+(n-1)4 =49
(n-1)4 =49+11
(n-1)4 = 60
n-1 = 60/4
n-1 = 15
n= 15 +1 =16
number of terms are in AP is 16
middle terms or 8th and 9th terms
a8 = a+7d = -11+7*4 = -11+28 = 17
a9 = a +8d = -11+8*4 =-11+32 = 21
Answered by
100
-11 , -7 , -3 ......... 49
In given ap ,
a = -11
d = -7 - (-11) = -7 + 11 = 4
An = 49
An = a + ( n - 1 ) d
49 = -11 + ( n - 1 ) 4
49 + 11 = ( n - 1 ) 4
60 / 4 = ( n - 1 )
n - 1 = 15
n = 15 + 1
n = 16
So the middle most term is 8 th or 9 th term
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