Question

* Find the middle term factor.
(I) 4s^2-4s+1​

Answer 1

Answer:

$s = \frac{1}{2} \: and \: \frac{1}{2}$

Step-by-step explanation:

${4s}^{2} - 2s + 1$

Splitting the middle term:-

${4s}^{2} - 2s - 2s + 1$

$2s(2s - 1) - 1(2s - 1)$

$(2s - 1)(2s - 1)$

$= > s = \frac{1}{2} and \frac{1}{2}$

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Answer 2

4s^2 -  4s + 1

answer:

4s^2 - 2s -2s + 1

= 2s(2s-1)  -1 (2s-1)

= (2s-1) (2s-1)

0

TO FIND ZEROES

2s-1=0

2s=0+1

2s=1

s=1/2

2s-1=0

2s=0+1

2s=1

s=1/2

so the zeroes will be

(1/2) (1/2)

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