Find the middle term of the A.P. 3, 8, 13,......, 253
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Answered by
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Step-by-step explanation:
ATQ. the last number in the series is 253
Therefore Tn= 253
formula of Tn = a + (n-1) d
Here a= 3 (first term)
d= 5 (common difference between the numbers)
putting the values we get
Tn = 3 + (n-1) 5 = 253
=》 3 + 5n - 5 = 253
=》 5n- 2= 253
=》5n= 253+2
=》 n= 255/5
=》 n= 51
Therefore number of terms in this series is 51
So middle term will be 26th term
now a26 = a + (n-1) d
= 3 + (26-1) 5
= 3+ 25× 5
= 3+ 125
= 128
Therefore middle term will be 128
Answered by
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Solution :
- First term = 3
- Common difference = 5
- Last term = 253
⇒ An = a + ( n - 1 ) d
→ 3 + (n-1) 5 = 253
→ 3 + 5n - 5 = 253
→ 5n- 2= 253
→ 5n= 253+2
→ n= 255/5
→ n= 51
There are 51 terms in this series
So middle term will be 26th term
A26 = a + 25d
→ 3+ 25× 5
→ 3+ 125
→ 128
Therefore middle term will be 128
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