find the middle term of the AP 10, 7, 4....., (-62)
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last term l is given = -62
first term a is given = 10
common difference d is 7-10=-3, 4-7=-3
number of term in AP n=(l-a)/d+1
n=(-62-10)/-3+1
n=(-72/-3)+1
n=24+1
n=25
since total terms are 25
so middle term is 13th term
again use n=(l-a)/d+1
this time total no. of term n=13
last term is 13th term, common difference is same as 3, first term is same as 10
now 13=(l-10)/-3+1
12=(l-10)/-3
-36=l-10
l=-26
so the middle term (13th term) is -26
Ans: -26
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