Question

find the middle term of the AP root 8, root18, root32........ 16root2​

Answer 1

Step-by-step explanation:

√8=2√2

√18=3√2

√32=4√2

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16√2

d=3√2-2√2=√2

so the terms be

4√2+√2=5√2,6√2,7√2,8√2,9√2,10√2,11√2,12√2,13√2,14√2,15√2

Answer 2

Answer:

middle term of the given AP is 9√2