Find the middle term of the ap with 17 terms whose 5th term is 23 and the common difference is -2
Answers
Answered by
27
Solution:-
Given: 5th term = 23 and common difference = - 2
So,
a₅ = 23
= a + 4d = 23
a + (4 × - 2) = 23
a = 23 + 8
a = 31
So, the first term is 31
There are total 17 terms in the given AP, so the middle term is a₉
So,
a₉ = a + (n-1)d
a₉ = 31 + (9 - 1) (- 2)
= 31 + (8 × -2)
= 31 - 16
a₉ = 15
So, the middle term is 15
Answer.
Given: 5th term = 23 and common difference = - 2
So,
a₅ = 23
= a + 4d = 23
a + (4 × - 2) = 23
a = 23 + 8
a = 31
So, the first term is 31
There are total 17 terms in the given AP, so the middle term is a₉
So,
a₉ = a + (n-1)d
a₉ = 31 + (9 - 1) (- 2)
= 31 + (8 × -2)
= 31 - 16
a₉ = 15
So, the middle term is 15
Answer.
Answered by
3
Answer:
Step-by-step explanation:
Given: 5th term = 23 and d = - 2
a₅ = 23
= a + 4d = 23
a + (4 × - 2) = 23
a = 23 + 8
a = 31
So, the first term is 31
There are total 17 terms in the given AP, so the middle term is a₉
So,
a₉ = a + (n-1)d
a₉ = 31 + (9 - 1) (- 2)
= 31 + (8 × -2)
= 31 - 16
a₉ = 15
answer is 15
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