Question

find the middle term of the expansion (3x-x^3/6)^8

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Answer 1

Step-by-step explanation:

since general term of any binomial expansion is

ⁿCr (a^n-r)b^r for any r+1nth term

here middle term is 5th term i.e r+1=5 so r=4

so the middle term is

8C4 (3x)⁴(-x^3/6)⁴

-8C4(3x)⁴(x^3/6)⁴...this is the middle term

Answer 2

Step-by-step explanation:

-420*3^4/3^4*x^12/2^4

-420/16*x^12