find the middle term of the expansion of x square + 3 by X into a power of 20
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184576×59049
Step-by-step explanation:
the given expansion is
(x² + 3)²°
x²°
so we have n + 1 terms
which means we have 20 + 1 terms
so the middle term will be 11 th term
the 11 term of the expansion of given form is
( x + 3/x )²°
so we get
t(r + 1) = ( nCr )(x^ n-r)((x/3)^r)
t11 =( 20C10 ) (x^10)(3/x)^10
we get ...
(184756)(59049)
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