Find the middle term of the sequence formed by all numbers 9 and 95,which leave a remainder 1 when divided by 3. Also find the sum of the numbers on both sides of the middle term separately.
Answers
Answered by
15
HELLO DEAR,
the AP will be 10,13,.....94
by substituting 94 in a+(n-1)d,we will get n=29
therefore the middle term will be 15th term =52
sum of terms up to middle term=15/2[2*10+14*3]=465
if we take the AP in reverse order then 94,91....10
sum of up to middle term=15/2[52+94]=1095
I HOPE ITS HELP YOU DEAR,
THANKS
the AP will be 10,13,.....94
by substituting 94 in a+(n-1)d,we will get n=29
therefore the middle term will be 15th term =52
sum of terms up to middle term=15/2[2*10+14*3]=465
if we take the AP in reverse order then 94,91....10
sum of up to middle term=15/2[52+94]=1095
I HOPE ITS HELP YOU DEAR,
THANKS
Manishpaul:
bheju
??
AB is a chord of circle with center O. At B, a tangent PB is drawn such that its length is 24 cm. The distance of P from the centre is 26 cm. If the chord AB is 16 cm, find its distance from the centre.
hey bhai
inbox me a
abhi coching ja rha hun
bad me btaunga
koi nhi bhai
aap bad me bhej digiyega
brainliest plz
Similar questions