Question

Find the middle term of the sequence formed by all three-digit numbers which leaves
remainder 3 when divided by 4. Also, find the sum of all numbers on both sides of the mi
term​

Answer 1

Now, all three digit-numbers that leave a remainder 3 when divided by 4 are 103, 107, 111, 115 , ..., 999, which forms an AP. Here, a = 103 and d = 4. Thus, the middle term of the sequence is 551.