Math, asked by Pankhi5, 1 year ago

Find the middle term of the sequence formed by all three digit numbers which leave a reminder 5 when divided by 7. Also find the sum of all numbers on both sides of the middle term separately.

Answers

Answered by ritik987
5
A.P: 103, 110, 117, ...., 999

a = 103  d = 7

n be the number of terms

= 999

103 + (n - 1)7 = 999

103 + 7n - 7 = 999

7n + 96 = 999

7n = 903

n = 129

Middle term =  term =  = a + 64d = 103 + 64 x 7 = 551

=  [2a + (n - 1)d]

=  [2 x 103 + 63 x 7] = 20704

=  [2 x 103 + 128 x 7] = 71079

- ( + 551) = 71079 - (20704 + 551) = 48924

Pankhi5: Can you be a little more specific in the last part of the answer.
ritik987: Sry i can not type now my hand is raining I have got ingure other wise I would have helped u
Pankhi5: Okay, Fine.
ritik987: Sry for inconvenience
Pankhi5: i can understand
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