Find the middle term (s) in the expansion of
1
i) (3x + 7y)10
ii) 3x +1/
2ypower 4
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- To find :- Middle term in the expansion of (1+3x+3x2+x3)2n.
solution :-
(1+3x+3x2+x3)2n=[(1+x)3]2n (∵ we know (a+b)3=a3+b3+3a2b+3ab2)
=(1+x)6n
Here Power =6n=2(3n)=even
Here Total no. of terms are odd.
So, There are only one middle term
i.e. (26n)th term=(3n)th term
T3n is to be find now,
we know formula for general term.
Tr+1=nCrxn−r.yr in expansion of (x+y)n.
T3n=6nC(3n−1)x(3n−1)⟺ final answer
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