find the middle term (s) in the expansion of (×- 1/ x) 2n
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1
Answer:
1.3.5...(2n−1)
2
n
x
n
Step-by-step explanation:
Middle term in the expansion of (1+x)
2n
; is =t
n+1
=
2n
C
n
.1
2n−n
.x
n
=
(2n−n)!n!
(2n)!
.x
n
=
(n!)(n!)
2n
(2n−1)(
2n−2
)(2n−3)....
4
×3×
2
×1
.x
n
=
(n!)(n!)
2
n
[n(n−1)(n−2)....×2×1][(2n−1)(2n−3)....3×1]
x
n
=
n!
(2n−1)(2n−3)....3×1
2
n
x
n
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