Question

find the midpoint of (69-4,5c) and (4b+4,-5c+2).​

Answer 1

$hola \: mate \: \infty$

Let, (x1 ,y1) and (x2, y2) be any two points

then their mid point is :

$( \frac{(x1 + x2)}{2} \: \: \: \: \: \frac{(y1 + y2)}{2} )$

Here, The give points are (65, 5c) and (4b+4 , (-5c+2))

=} Their mid point is :

$( \frac{(65 + 4b + 4)}{2} \: \: \: \: \frac{(5c - 5c + 2)}{2} )$

$( \frac{69 + 4b}{2} \: \: \frac{2}{2} )$

$( \frac{69}{2} + 2b) \: \: \: \: (1)$

Therefore, the mid point of given points is ,

(69/2 + 2b , 1)