find the midpoint of the line joining (0,0) (8,-5)
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Here is your solution
Given :-
Line joining (0,0) (8,-5)
We have to find midpoint of x and y
M=[(x1+x2/2),(y1+y2/2)]
X=0+8/2
x=4
Y=0+(-5)/2
Y=-5/2
Midpoint of the line joining (0,0) (8,-5) is (4,-5/2)
Given :-
Line joining (0,0) (8,-5)
We have to find midpoint of x and y
M=[(x1+x2/2),(y1+y2/2)]
X=0+8/2
x=4
Y=0+(-5)/2
Y=-5/2
Midpoint of the line joining (0,0) (8,-5) is (4,-5/2)
VemugantiRahul:
yes !
Answered by
7
Hi there!
Here's the answer
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶ Mid point of line joining the points (x1,y1) and (x2,y2) is given by
M = [ (x1+x2)/2 , ( y1+y2)/2 ]
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Given,
(x1,y1) = (0,0)
(x2,y2) = (8, -5)
Substituting values, we get,
M = [ (0+8)/2 , (0+(-5))/2 ]
M = (4 , -2.5 )
•°• The midpoint of the line joining (0, 0) (8, -5) = (4, -2.5)
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
©#£®$
:)
Hope it hels
Here's the answer
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
¶ Mid point of line joining the points (x1,y1) and (x2,y2) is given by
M = [ (x1+x2)/2 , ( y1+y2)/2 ]
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Given,
(x1,y1) = (0,0)
(x2,y2) = (8, -5)
Substituting values, we get,
M = [ (0+8)/2 , (0+(-5))/2 ]
M = (4 , -2.5 )
•°• The midpoint of the line joining (0, 0) (8, -5) = (4, -2.5)
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
©#£®$
:)
Hope it hels
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