Question

find the midpoint of the line segment joining the points (2,7) and (12,-7)​

Answer 1

Given :-

• The mid point of the line segment joining the points (2, 7) and (12, -7)

Solution :-

The mid point formula states that the line segment joining the points p(x1 , y1) and Q(x2,y2) is (x1 + x2 / 2 + y1 + y2 /2)

Let's compare the given point with x

and y

x1 = 2 , y1 = 7 and x2 = 12 , y2 = -7

Now , By using Mid point formula

x = x1 + x2 / 2

x = 2 + 12 / 2

x = 14 / 2

x = 7

and

y = y1 + y2 / 2

y = 7 + ( -7 ) / 2

y = 7 - 7 / 2

y = 0/2

y = 0

Hence, The coordinates of mid point are ( 7 , 0 )

Explore More :-

• Distance formula

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

• Section Formula

x = m1x2 + m2x1 / m1 + m2

y = m1y2 + m2y1 / m1 + m2

Answer 2

Answer:

Mid point of the line segment is (7,0)

Step-by-step explanation:

Question:

Find the midpoint of the line segment joining the points (2,7) and (12,-7)

Given:

• Two points: (2,7) and (12,-7)

To find:

Mid-point of the line segment

Formula used:

Mid point of x = $\sf\dfrac{x_1+x_2}{2}$

Mid point of y = $\sf\dfrac{y_1+y_2}{2}$

Solution:

Step 1:

Mid point of x = $\sf\dfrac{2+12}{2}$

Mid point of x = $\sf\dfrac{14}{2}$

Mid point of x = 7

Step 2:

Mid point of y = $\sf\dfrac{7+(-7)}{2}$

Mid point of y = $\sf\dfrac{0}{2}$

Mid point of y = 0

So, mid point of the line segment is (7,0)