Question

Find the minimum and maximun Value of
$\frac{x + 1}{2 {x}^{2} + x + 1}$
$\frac{ {x}^{2} + 1}{ {x}^{2} + x + 1}$
please urgent the best will be marked as brainliest...​

Answer 1

Answer:

y=

x

2

+3x+4

x

2

−3x+4

⇒(y−1)x

2

+3(y+1)x+4(y−1)=0

As x is real, discriminant ≥0

⇒9(y+1)

2

−16(y−1)

2

≥0

⇒−7y

2

+50y−7≥0

⇒(y−7)(7y−1)≤0

∴y∈[

7

1

,7]

i.e. Maximum value of expression is 7 and minimum value is

7

1

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