Find the minimum diameter of a steel wire which is used to raise a load of 5000N if the stress in the wire is not to exceed 95 MN/m2
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Given,
F=W=5000N
Stress = 95 MN/m²
=95 × 1000000 N/m²
To find,
Minimum diameter of the steel wire =?
Solution,
Using the formula of stress,
Stress=F/A = F/πR²
⇒r² = F/π stress
⇒r = √F/π stress
r=√5000/3.14×95×1000×1000
r=√5×10⁻²/3.14×95
r= 10⁻¹× 0.0409
r= 4.09×10⁻³m
Therefore, Diameter of steel wire = 2r
D= 2r = 2×4.04×10⁻³
D= 8.18×10⁻³
Hence, the diameter of the wire is 8.18×10⁻³.
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