Question

find the minimum diameter of steel wire which is used to raise a load of 4000 N if the stress in the rod is not exceed 95mn/m2​

Answer 1

Answer:

Answer: d

Explanation: As stress = load / area

Area = load/stress

Also, area is π/4 D2 so π/4 D2 = 4000 / 95

And D = 7.32.

Answer 2

Answer:

Explanation: Answer: d

Explanation: As stress = load / area

Area = load/stress

Also, area is π/4 D2 so π/4 D2 = 4000 / 95

And D = 7.32.

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