Find the minimum F to prevent the slip of 5 kg block Options 30N 25N 22N 26N
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Explanation:
Fsin37+mgcos37=N
Frictional force = mgsin37-Fcos37
10(mgsin37-Fcos37) =Fsin37+mgcos37
10(3mg-4F)=3F+4mg
26mg=43F
F=25N
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