Question

Find the minimum prime number which has divide 9^1 +2187^4

Answer 1

N=9^1+2187^4

N=3^2+3^28

N=odd+odd makes even

N=even number

N=2

Answer 2

Answer:

3

Step-by-step explanation:

9¹+81²+243³+2187⁴

(3²)¹+(3⁴)²+(3⁵)³+(3⁷)⁴

=>3²+3⁸+3¹⁵+3²⁸

Since 3 is common in all

and It is a prime no.

The number is divisible by 3 as the least prime number

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