Find the minimum speed required by a person standing 5 m behind a bus, to catch the bus in one minute which is moving at a speed of 600 m min?
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Answer:
605m/s
Step-by-step explanation:
Use relative velocity concept
Stop the bus and its velocity in opposite direction to man
Now let the man's speed be x
So resultant speed of man will be x-600
S=5m
u=x-600m/min
t=1min
Apply s=ut
5=(x-600)*1
x=605m/s
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