Question

find the minimum total resistance that can be secured by the combination of 4 ohm, 8ohm, 12ohm, 24ohm.​

Answer 1

Answer:

combination of 4 ohm, 8ohm, 12ohm, 24ohm

Answer 2

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$a)Highest \: will \: be \: by \: series  \\ =4+12+8+24=48o \: hms$

$(b)Lowest \: will \: be \: by \: parallel \\  =1/R=1/4+1/8+1/24+ \\ = 12/24 so R=2$