Question

Find the minimum value for 2 cosx + 2 sin x

Answer 1

sin^2x+ cos^2x(cos^2x) =sin^2x+ cos^2x(1-sin^2x) =sin^2x +cos^2x -cos^2x sin^2x =1- (sinxcosx)^2 min value : 1- (1/2)^2 =3/4 (for minimum we put max value of sinxcosx) max value : 1-0 =1 (for max we put min value of sinxcosx due to -ve sign in the statement)

Answer 2

Step-by-step explanation:

2(-1) + 2(-1) = -4

answer is -4.

hope it helps you....